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Find the equation of a circle with Centre ( - a, - b) and radius \(\sqrt{a^2 - b^2}\)

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The general form of the equation of a circle is: 

(x - h)2 + (y - k)2 = r2 

Where, (h, k) is the centre of the circle. 

r is the radius of the circle.

Substituting the centre and radius of the circle in he general form:

⇒ (x - ( - a ))2 + (y - ( - b))2 = √(a22 - b22)2 

⇒ (x + a )2 + (y + b)2 = a2 - b2 

⇒ x2 + 2xa + a2 + y2 + 2yα + b2 = a2 - b2 

⇒ x2 + 2xa + y2 + 2yα = a2 - 2b

⇒ x2 + y2 + 2a(x + y) = a2 - 2b

⇒ x2 + y2 + 2a(x + y) = a2 - 2b2 

Ans; equation of a circle with Centre ( - a, - b) and radius is:

⇒ x2 + y2 + 2a(x + y) = a2 - 2b2

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