The point of intersection of two diameters is the centre of the circle.
∴ point of intersection of two diameters x – y = 9 and x – 2y = 7 is (11, 2).
∴ centre = (11, 2)
Area of a circle = πr2
38.5 = πr2
⇒ r2 = \(\frac{38.5}{\pi}\)
⇒ r2 = 12.25 sq.cm
the equation of the circle is:
(x - h)2 + (y - k)2 = r2
Where, (h, k) is the centre of the circle.
r is the radius of the circle.
⇒ (x - 11)2 + (y - 2)2 = 12.25
(x - 11)2 + (y - 2)2 = 12.25