2 or more circles are said to be concentric if they have the same centre and different radii.
Given, x2 + y2 + 4x + 6y + 11 = 0
The concentric circle will have the equation
x2 + y2 + 4x + 6y + c’ = 0
As it passes through P(5, 4), putting this in the equation
52 + 42 + 4 x 5 + 6x 4 + c = 0
25 + 16 + 20 + 24 + c = 0
c = -85
The required equation is
x2 + y2 + 4x + 6y - 85 = 0