Given x2 + y2 – 6x + 5y – 7 = 0
Centre(3,-\(\frac{5}{2}\))
As ( - 1, 3) & (∝, β) are the 2 extremities of the diameter, using mid - point formula we can write
\(\frac{∝-1}{2}\) = 3
⇒ ∝ = 7
and \(\frac{\beta+3}{2}\) = \(-\frac{5}{2}\)
⇒ β = -8
(∝, β) = (7, - 8)