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If cosx = -3/5 and π < x < 3π/2, find the values of cos 2x

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If cosx = -3/5 and π < x < 3π/2, find the values of cos 2x

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Given: cosx = \(\frac{-3}{5}\)

To find: cos2x

We know that,

cos 2x = 2cos2x – 1

Putting the value, we get

∴ cos2x = \(-\frac{7}{25}\)

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