Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
147 views
in Geometric Progressions by (175 points)
recategorized by

Find the sum of 10 terms of a GP whose 8th term is 768 and the common ratio is 2.

Please log in or register to answer this question.

1 Answer

0 votes
by (30.3k points)

t8 = 768

= ar7

r = 2

t10 = ar9 

= ar7 × r × r

= 768 × 2 × 2

= 3072

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...