Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Trigonometry by (29.9k points)
closed by

Prove that

\(\frac{1\,-\,cos2x\,+\,sinx}{sin2x\,+\,cosx}=tanx\)

1 - cos2x + sinx/sin2x + cosx = tanx

1 Answer

+1 vote
by (30.3k points)
selected by
 
Best answer

To prove: \(\frac{1\,-\,cos2x\,+\,sinx}{sin2x\,+\,cosx}=tanx\)

Taking LHS,

We know that,

1 – cos 2x = 2 sin2x & sin 2x = 2 sinx cosx

Taking sinx common from the numerator and cosx from the denominator

\(\frac{sinx}{cosx}\)

= tanx  [∵ tanθ = \(\frac{sin\theta}{cos\theta}\)]

= RHS

∴ LHS = RHS

Hence Proved

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...