We know that,
Probability of occurrence of an event
= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)
Let T be tails and H be heads
Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH
Desired outcomes are exactly two tails. So, desired outputs are TTH, THT, HTT
Total no. of outcomes are 8 and desired outcomes are 3
Therefore, the probability of getting exactly 2 tails = \(\frac{3}{8}\)
Conclusion: Probability of getting exactly two tails is \(\frac{3}{8}\)
