We know that,
Probability of occurrence of an event
= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)
Let T be tails and H be heads
Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH
Desired outcomes are at least two tails. So, the desired outputs are TTH, THT, HTT, TTT
Total no. of outcomes are 8 and desired outcomes are 4
Therefore, the probability of getting at least 2 tails = \(\frac{4}{8}\) = \(\frac{1}{2}\)
Conclusion: Probability of getting at least two tails is \(\frac{1}{2}\)