We know that,
Probability of occurrence of an event
= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)
Total no. of outcomes are 52
Desired output is a number greater than 3 and less than 10.
There will be four sets of each card naming A, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K. So, there will be a total of 24 cards between 3 and 10
Therefore, the probability of picking card between 3 and 10 = \(\frac{24}{52}\) = \(\frac{6}{13}\)
Conclusion: Probability of picking a card between 3 and 10 is \(\frac{6}{13}\)