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A card is drawn at random from a well-shuffled pack of 52 cards. What is the probability that the card bears a number greater than 3 and less than 10?

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We know that, 

Probability of occurrence of an event

  = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) 

Total no. of outcomes are 52 

Desired output is a number greater than 3 and less than 10. 

There will be four sets of each card naming A, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K. So, there will be a total of 24 cards between 3 and 10 

Therefore, the probability of picking card between 3 and 10 = \(\frac{24}{52}\) = \(\frac{6}{13}\)

Conclusion: Probability of picking a card between 3 and 10 is \(\frac{6}{13}\)

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