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Tickets numbered from 1 to 12 are mixed up together, and then a ticket is withdrawn at random. Find the probability that the ticket has a number which is a multiple of 2 or 3.

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Best answer

We know that, 

Probability of occurrence of an event

  = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) 

Total no. of outcomes are 12 

Desired output is picking a number which is multiple of 2 or 3. So, desire outputs are 2, 3, 4, 6, 8, 9, 10, 12. Total no. of desired outputs are 8

Therefore, the probability of getting a number which is multiple of 2 or 3

\(\frac{8}{12}\)

=   \(\frac{2}{3}\)

Conclusion: Probability of picking a ticket which is multiple of 2 or 3 is \(\frac{2}{3}\)

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