We know that,
Probability of occurrence of an event
= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)
Total no. of outcomes are 12
Desired output is picking a number which is multiple of 2 or 3. So, desire outputs are 2, 3, 4, 6, 8, 9, 10, 12. Total no. of desired outputs are 8
Therefore, the probability of getting a number which is multiple of 2 or 3
= \(\frac{8}{12}\)
= \(\frac{2}{3}\)
Conclusion: Probability of picking a ticket which is multiple of 2 or 3 is \(\frac{2}{3}\)