Given: sin x = \(\frac{3}{5}\) and 0 < x < \(\frac{\pi}{2}\)i.e, x lies in Quadrant I and all the trigonometric
ratios are positive in quadrant I.
To Find: tan\(\frac{x}{2}\)
Formula used:
tan\(\frac{x}{2}=\frac{sinx}{1+cosx}\)
Now, cos x = \(\sqrt{1-sin^2x}\)
(∵ cosx is positive in | quadrant)
Hence, tan\(\frac{x}{2}\) = \(\frac{1}{3}\)