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If sinx = 3/5 and 0 < x < π/2, find the value of tanx/2.

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Given: sin x = \(\frac{3}{5}\) and 0 < x < \(\frac{\pi}{2}\)i.e, x lies in Quadrant I and all the trigonometric

ratios are positive in quadrant I.

To Find: tan\(\frac{x}{2}\)

Formula used:

tan\(\frac{x}{2}=\frac{sinx}{1+cosx}\)

Now, cos x = \(\sqrt{1-sin^2x}\)

(∵ cosx is positive in | quadrant)

Hence, tan\(\frac{x}{2}\) = \(\frac{1}{3}\)

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