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If A and B are two mutually exclusive events such that P(A) = (1/2) and P(B) = (1/3), find P(A or B).

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Given : A and B are mutually exclusive events 

P(A) = \(\frac{1}{2}\), P(B) = \(\frac{1}{3}\) 

To find : P(A or B) 

Formula used : P(A or B) = P(A) + P(B) - P(A and B) 

For mutually exclusive events A and B, P(A and B) = 0 

Substituting in the above formula we get, 

P(A or B) = \(\frac{1}{2}+\frac{1}{3}\) + – 0 

P(A or B) = \(\frac{5}{6}\)

P(A or B) = \(\frac{5}{6}\)

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