Given : A and B are mutually exclusive events
P(A) = \(\frac{1}{2}\), P(B) = \(\frac{1}{3}\)
To find : P(A or B)
Formula used : P(A or B) = P(A) + P(B) - P(A and B)
For mutually exclusive events A and B, P(A and B) = 0
Substituting in the above formula we get,
P(A or B) = \(\frac{1}{2}+\frac{1}{3}\) + – 0
P(A or B) = \(\frac{5}{6}\)
P(A or B) = \(\frac{5}{6}\)