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in Geometric Progressions by (15.9k points)

Express the recurring decimal 0.125125125 …. = 0. \(\overline{125}\) as a rational number.

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1 Answer

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by (15.3k points)

Let, x=0.125125125… …(i) 

Multiplying this equation by 1000 on both the sides so that repetitive terms cancel out and we get: 

1000x =125.125125125… …(ii) 

Equation (ii) - (i), 

⇒ 1000x-x =125.125125125-0.125125125 =125 

⇒ 999x =125

⇒ x = \(\frac{125}{999}\)

⇒ 0.\(\overline{125}\) = \(\frac{125}{999}\)

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