Let, x=0.125125125… …(i)
Multiplying this equation by 1000 on both the sides so that repetitive terms cancel out and we get:
1000x =125.125125125… …(ii)
Equation (ii) - (i),
⇒ 1000x-x =125.125125125-0.125125125 =125
⇒ 999x =125
⇒ x = \(\frac{125}{999}\)
⇒ 0.\(\overline{125}\) = \(\frac{125}{999}\)