Given : A die is thrown twice
To find : Probability that at least one of the two throws comes up with the number 4
The formula used : Probability
= \(\frac{favourable\,number\,of\,outcomes}{Total\,no.of\,outcomes}\)
A die is numbered from 1 to 6
When a die is thrown twice, total number of outcomes = 62 = 36
Favourable outcomes =
{(4,1) ,(4,2) ,(4,3) ,(4,4) ,(4,5) ,(4,6) ,(1,4) ,(2,4) ,(3,4) ,(5,4) , (6,4)}
Favourable number of outcomes = 11
Probability that at least one of the two throws comes up with the number 4 = \(\frac{11}{36}\)
The probability that at least one of the two throws comes up with the number 4 = \(\frac{11}{36}\)
