Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Limits by (40.3k points)
closed by

Evaluate the following limit : \(\lim\limits_{\text x \to0}\cfrac{2-\sqrt3\,cos\,\text x-sin\,\text x}{(6\text x-\pi)^2} \)

lim(x→π/6) (2 - √3 cos x - sin x)/(6x - π)2

1 Answer

+1 vote
by (38.4k points)
selected by
 
Best answer

\(\lim\limits_{\text x \to0}\cfrac{2-\sqrt3\,cos\,\text x-sin\,\text x}{(6\text x-\pi)^2} \)

lim(x→π/6) (2 - √3 cos x - sin x)/(6x - π)2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...