Question

For a Carnot engine, the source is at 500K and the sink at 300K.What is efficiency of this engine?

 A) 0.2 

B) 0.4 

C) 0.6 

D) 0.3

Answer 1

Answer: B) 0.4

Explanation:

Given that, T₁ = 500K, T₂=300 K

\(\eta=\frac{T_1-T_2}{T_1}= \frac{500-300}{500}=\frac{200}{500}=0.4\)