Given: Coefficient of variation of two distributions are 60% and 80% respectively, and their standard deviations are 21 and 16 respectively.
Need to find: Arithmetic means of the distributions.
For the first distribution,
Coefficient of variation (CV) is 60%, and the standard deviation (SD) is 21.
We know that,
For the first distribution,
Coefficient of variation (CV) is 80%, and the standard deviation (SD) is 16.
We know that,
CV = \(\frac{SD}{Mean}\times100\)
Mean = \(\frac{SD}{CV}\times100\)
Mean = \(\frac{21}{60}\times100\)
Mean = 35
For the first distribution,
Coefficient of variation (CV) is 80%, and the standard deviation (SD) is 16.
We know that,
CV = \(\frac{SD}{Mean}\times100\)
Mean = \(\frac{SD}{CV}\times100\)
Mean = \(\frac{16}{80}\times100\)
Mean = 20
Therefore, the arithmetic mean of 1st distribution is 35 and the arithmetic mean of 2nd distribution is 20.