In case of heights,
Mean = 63.2 inches and SD = 11.5 inches.
So, the coefficient of variation,
CV = \(\frac{SD}{Mean}\times100\)
CV = \(\frac{11.5}{63.2}\times100\) = 18.196
In case of weights,
Mean = 63.2 inches and SD = 5.6 inches.
So, the coefficient of variation,
CV = \(\frac{SD}{Mean}\times100\)
CV = \(\frac{5.6}{63.2}\times100\) = 8.86
CV of heights > CV of weights
So, heights show more variability