For what valve of k is the following function ƒ(x) = {x^2 - 9/x-3, when x ≠ 3; k, when x = 3 is continuous at x=3

Question

For what valve of k is the following function

\(f(x) = \begin{cases} \frac{x^2-9}{x-3} , & \quad \text{when} \,\text{x≠3;}\\ k , & \quad \text{when}\, \text{x=3} \end{cases}\) is continuous at x = 3

Answer 1

Since, f(x) is continuous at x=3

k = 9