Question

Class 11 Physics MCQ Questions of Motion in a Straight Line with Answers?

Answer 1

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Practice MCQ Questions for class 11 Physics Chapter-Wise

1. A boy starts from a point A, travels to a point B at a distance of 3 km from A and returns to A. If he takes two hours to do so, his speed is

(a) 3 km/h
(b) zero
(c) 2 km/h
(d) 1.5 km/h

2. A boy starts from a point A, travels to a point B at a distance of 1.5 km and returns to A. If he takes one hour to do so, his average velocity is

(a) 3 km/h
(b) zero
(c) 1.5 km/h
(d) 2 km/h

3. Which one of the following is the unit of velocity?

(a) kilogram
(b) metre
(c) m/s
(d) second

4. A body starts from rest and travels for t second with uniform acceleration of 2 m/s². If the displacement made by it is 16 m, the time of travel t is

(a) 4 s
(b) 3 s
(c) 6 s
(d) 8 s

5. A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s .Then t is

(a) 10 s
(b) 5 s
(c) 20 s
(d) 6 s

6. A body starts from rest. If it travels with an acceleration of 2 m/s², its displacement at the end of 3 seconds is

(a) 9 m
(b) 12 m
(c) 16 m
(d) 10 m

7.  A body starts from rest and travels with uniform acceleration of 2 m/s². If its velocity is v after making a displacement of 9 m, then v is

(a) 8 m/s
(b) 6 m/s
(c) 10 m/s
(d) 4 m/s

8. A body starts from rest and travels for five seconds to make a displacement of 25 m if it has travelled the distance with uniform acceleration a then a is

(a) 3 m/s²
(b) 4 m/s²
(c) 2 m/s²
(d) 1 m/s²

9. A body is moving along a straight line path with constant velocity. At an instant of time the distance travelled by it is S and its displacement is D, then

(a) D = S
(b) D > S
(c) D < S
(d) None of these

10. The location of a particle has changed. What can we say about the displacement and the distance covered by the particle?

(a) Neither can be zero
(b) One may be zero
(c) Both may be zero
(d) One is +ve, other is –ve

11. The displacement of a body is zero. The distance covered

(a) may or may not be zero
(b) is not zero
(c) is zero
(d) depends upon the acceleration

12. The numerical ratio of displacement to distance for a moving object is

(a) equal to or less than 1
(b) always equal to 1
(c) always less than 1
(d) always more than 1

13. Which of the following can be zero, when a particle is in motion for some time?

(a) Displacement
(b) None of these
(c) Distance
(d) Speed

14. Which of the following is a one dimensional motion?

(a) Motion of train running on a straight track
(b) Motion of satellite
(c) Motion of air particle
(d) Motion of snake

15. The distance travelled by a body is directly proportional to the time taken. Its speed

(a) remains constant
(b) decreases
(c) increases
(d) becomes zero

16. The slope of velocity-time graph for motion with uniform velocity is equal to

(a) zero
(b) final velocity
(c) initial velocity
(d) none of these

17. The ratio of the numerical values of the average velocity and average speed of a body is

(a) unity or less
(b) less than unity
(c) unity
(d) unity or more

18. The graph between displacement and time for a particle moving with uniform acceleration is a/an

(a) parabola
(b) ellipse
(c) straight line parallel to time axis
(d) straight line with a positive slope

19.  The acceleration of a moving body can be found from

(a) slope of the velocity- time graph
(b) slope of distance- time graph
(c) area under distance - time graph
(d) area under velocity - time graph

20. Velocity time curve for a body projected vertically upwards is

(a) straight line
(b) ellipse
(c) parabola
(d) hyperbola

21. A body is thrown upwards and reaches half of its maximum height. At that position

(a) its acceleration is constant
(b) its velocity is zero
(c) its velocity is maximum
(d) its acceleration is minimum

22. A body moves from rest with a constant acceleration of 5 m/s². Its instantaneous speed (in m/s) at the end of 10 sec is  

(a) 50
(b) 5
(c) 2
(d) 0.5

23. The acceleration of the particle is defined as

(a) change of velocity to displacement
(b) change of velocity to time
(c) change of velocity to speed
(d) change of velocity to distance

24. If a body travels with constant acceleration, which of the following quantities remains constant?

(a) None of these
(b) Time
(c) Velocity
(d) Displacement

25. The displacement of a particle as a function of time is shown in the figure. The figure shows that

(a) The particle starts with certain velocity but the motion is retarded and finally the particle stops
(b) The velocity of the particle is constant throughout
(c) The acceleration of the particle is constant throughout
(d) The particle starts with constant velocity, then motion is accelerated and finally the particle moves with another constant velocity

Answer 2

1. Answer: (a) 3 km/h

Explanation: Speed of a body is the rate of change of distance covered by the body with respect to time.

Speed = total distance covered/total time taken

Total distance covered by the boy = Distance between A and B + Distance between B and A 

= 3 km + 3 km = 6 km.

Speed of the boy = 6/2 = 3 km/h

2. Answer: (b) zero

Explanation: Average Velocity = Displacement  / Time taken

Displacement = Final Position - Initial Position

Hence Final Position = Initial Position

⇒ Displacement =  0

Average Velocity = 0/1 = 0 

3. Answer: (c) m/s

Explanation: The SI unit of velocity is meter per second (m/s).

4. Answer: (a) 4 s

Explanation: s = ut + 1/2 at²

16= 0 + 1/2 \(\times\) 2 \(\times\) t²

16 = t²

thus t = 4

5. Answer: (b) 5 s

Explanation: a =2m/s²

u = 0m/s

time = t sec

v = 10 m/s

a = v - u/t

2 =10 - 0/t

2t = 10 - 0

2t = 10

t =10/2

t = 5sec

6. Answer: (a) 9 m

Explanation: s = ut + 1/2 at²

16= 0(t) + 1/2 \(\times\) 2 \(\times\) 3²

s = 1/2 \(\times\) 2 \(\times\) 3²

s = 9

Displacement at the end of 3 sec = 9 m

7. Answer: (b) 6 m/s

Explanation: V² - U² = 2as

⇒ V² - (0)² = 2 \(\times\) 2 \(\times\) 9

⇒ V² = 36

Final velocity (v) = 6 m/s

8. Answer: (c) 2 m/s²

Explanation: s = ut + 1/2 at²

25 = 0(t) + 1/2 \(\times\) a \(\times\) 5²

25 = 1/2 \(\times\) a \(\times\) 25

25/25 =1/2a

1 = 1/2a

1 \(\times\) 2/1 = a

a = 2 m/s²

9. Answer: (a) D = S

Explanation: In a straight line-path with constant velocity distance travelled = displacement ie, s= D.

10. Answer: (a) Neither can be zero

Explanation: When location of a particle has changed, it must have covered some distance and undergone some displacement.  As, initial and final position of body are different, so distance and displacement, both can neither be zero.

11. Answer: (a) may or may not be zero

Explanation: When displacement is zero, particle may be at rest, therefore, distance travelled = 0. Again, when displacement is zero, final position coincides with the initial position, distance travelled is not zero.

12. Answer: (a) equal to or less than 1

Explanation: As we know that the displacement is the shortest distance between two points. Thus distance may be equal to, or greater than, displacement. Hence, the ratio of displacement to distance is always equal to or less than 1.

13. Answer: (a) Displacement

Explanation: During some time interval, distance cannot be zero so as speed but displacement may be zero because final position of the particle may coincide with its initial position.

14. Answer: (a) Motion of train running on a straight track

Explanation: Motion of train on straight track is a one dimensional motion whereas everything else is a two dimensional or three dimensional activity. 

15. Answer: (a) remains constant

Explanation: speed = Distance/time . For Distance \(\propto\) time, the speed has to be constant.

16. Answer: (a) zero

Explanation: The velocity-time graph for a uniform motion is a st. line parallel to time axis. Its slope is zero.

17. Answer: (a) unity or less

Explanation: As displacement ≤ distance, therefore, the numerical ratio of average velocity to average speed is equal to or less than one but can never be more than one.

18. Answer: (a) parabola

Explanation: The graph between displacement and time for a particle moving uniform acceleration is a parabola.

19. Answer: (a) slope of the velocity- time graph

Explanation: The acceleration of a moving body is found from the slope of velocity -time graph. 

20. Answer: (a) straight line

Explanation: For a body projected vertically upwards,

Velocity at any instant of time is given by v = u_o− gt, which is a straight line with slope '−g' and intercept u₀.

21. Answer: (a) its acceleration is constant

Explanation: During the whole journey, the acceleration of the body would be the same as the acceleration due to gravity.The acceleration of the body = 9.8 m/s²

22. Answer: (a) 50

Explanation: v = u + at

v = 0 + 5 \(\times10\) 

v = 50 m/s

23. Answer: (c) change of velocity to time

Explanation: The acceleration of a particle is vector quantity means which have both magnitudes as well as direction. The acceleration of the particle is defined as the rate of change of velocity to time.

24. Answer: (a) None of these

Explanation: When any given body travels with a constant acceleration it is supposed to be in a uniform motion.

25. Answer: (a) The particle starts with certain velocity but the motion is retarded and finally the particle stops

Explanation: Initially the slope is decreasing and the slope = 0.

Thus velocity is decreasing as time increases, i.e. there is retardation and ultimately the particle stops. It must have obviously started with some velocity.

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