F(x) = x+1/x
Taking first derivative and equating it to zero to find extreme points.
F’(x) = 1 - 1/x2 = 0
X2 = 1
x = 1, x = -1
now to determine which of these is min. And max. We use second derivative.
f || (x) = 2/x2
f || (1) = 2 and f || (-1) = -2
since f || (1) is +ve it is minimum point while f || (-1) is –ve it is maximum point
max value- > f(-1) = -1+1/-1 = -2
min value- > f(1) = 1+1/1 = 2
hence maximum value is less than minimum value