Let I = \(\int\frac{dx}{cosx(5-4sinx)}\)
Put t = sinx
dt = cosxdx
A(1 + t)(5 - 4t) + B(1 - t)(5 - 4t) + C(1 + t)(1 - t) = 1
Now Putting 1 + t = 0
t = -1
A(0) + B(2)(9) + C(0) = 1
B = 1/18
Now Putting 1-t = 0
t = 1
A(2) + B(0) + C(0) =1
A = 1/2
Now Putting 5 - 4t = 0
t = 5/4
A(0) + B(0) + C (1 - 25/16) = 1
C = -16/9
From equation(1),we get,