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+1 vote
19.4k views
in Chemistry by (42.5k points)

2SO2(g) + O2(g) → 2SO3(g) 

The above reaction is carried out in a vessel starting with partial pressure PSO2 = 250m bar, PO2 = 750m bar and PSO3 = 0 bar . When the reaction is complete, the total pressure in the reaction vessel is ....... m bar. (Round off of the nearest integer).

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1 Answer

+1 vote
by (44.7k points)

2SO2(g) + O2(g) → 2SO3(g) 

Final total pressure = 625 + 250 = 875 m bar

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