∫dx/√{x - x^2} = ?

Question

\(\int\frac{dx}{\sqrt{x-x^2}}\) = ?

∫dx/√{x - x²}

A. sin^-1 (x – 1) + C 

B. sin^-1 (x + 1) + C 

C. sin^-1 (2x – 1) + C 

D. none of these

Answer 1

\(\int\frac{dx}{\sqrt{x-x^2}}\) = \(\int\frac{dx}{\sqrt{-x^2+x}}\)

= sin^-1(2x - 1) + c