∫dx/√{x^2 -16} = ?

Question

\(\int\frac{dx}{\sqrt{x^2-16}}\) =?

∫dx/√{x² -16}

A. sin^-1\((\frac{x}4)\) + c

B. log |x + \(\sqrt{x^2-16}\)| + c

C. log |x - \(\sqrt{x^2-16}\)| + c

D. none of these

Answer 1

\(\int\frac{dx}{\sqrt{x^2-a^2}}\) = log | x + \(\sqrt{x^2-a^2}\)|

\(\int\frac{dx}{\sqrt{x^2-4^2}}\) = log | x + \(\sqrt{x^2-16}\)|