For the cell
Cu(s) | Cu2+(aq) (0.1M) || Ag+ (aq) (0.01M) | Ag(s) the cell potential E1 = 0.3095 V
For the cell
Cu(s) | Cu2+ (aq) (0.01 M) || Ag+ (aq) (0.001 M) | Ag(s)
the cell potential = ....... x 10–2 V. (Round off the Nearest Integer). [Use : \(\frac{2.303RT}{F}\)= 0.059]