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+3 votes
14.4k views
in Chemistry by (42.5k points)

For the cell

Cu(s) | Cu2+(aq) (0.1M) || Ag+ (aq) (0.01M) | Ag(s) the cell potential E1 = 0.3095 V 

For the cell

Cu(s) | Cu2+ (aq) (0.01 M) || Ag+ (aq) (0.001 M) | Ag(s) 

the cell potential = ....... x 10–2 V. (Round off the Nearest Integer). [Use : \(\frac{2.303RT}{F}\)= 0.059] 

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1 Answer

+3 votes
by (44.7k points)

Answer is : 28

Cell reaction is :

From (1) and (2) , E2 = 0.28 V = 28 x 10–2 V

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