∫dx/√{4x^2 - 9} = ?

Question

\(\int\frac{dx}{\sqrt{4x^2-9}}\) = ?

∫dx/√{4x² - 9}

A.\(\frac{1}2\) log | x + \(\sqrt{4x^2-9}\)| + c

B.\(\frac{1}4\) log | x + \(\sqrt{4x^2-9}\)| + c

C.log | 2x + \(\sqrt{4x^2-9}\)| + c

D. none of these

Answer 1

\(\int\frac{dx}{\sqrt{(2x)^2-(3)^2}}\)

Put t = 2x 

dt = 2 dx