Given : A = \(\begin{bmatrix} 3& 1 \\[0.3em] 7 &5 \\[0.3em] \end{bmatrix}\), A2 + xI = yA.
A is a matrix of order 2 x 2
To find : x and y
Formula used :
Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
If A is a matrix of order a x b and B is a matrix of order c x d ,then matrix AB exists and is of order a x d ,
if and only if b = c
A2 is a matrix of order 2 x 2
It is given that A2 + xI = yA,
Equating similar terms in the given matrices,
16 + x = 3y and 8 = y,
hence y = 8
Substituting y = 8 in equation 16 + x = 3y
16 + x = 3 × 8 = 24
16 + x = 24
x = 24 – 16 = 8
x = 8
x = 8, y = 8