Question

The oxidation states of 'P' in H₄P₂O₇, H₄P₂O₅ and H₄P₂O₆, respectively, are : 

(1) 7, 5 and 6 

(2) 5, 4 and 3 

(3) 5, 3 and 4 

(4) 6, 4 and 5

Answer 1

Answer is (3) 5, 3 and 4 

oxidation states of 'P' in H₄P₂O₇, H₄P₂O₅ and H₄P₂O₆ is 5, 3 & 4 respectively

H₄P₂O₇

2x + 4(+1)+7(–2) = 0

x = + 5

H₄P₂O₅

2x + 4(+1) + 5 (–2) = 0 

x = + 3 

H₄P₂O₆

2x + 4 (+1) + 6 (–2) = 0 

x = + 4