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Evaluate the following integrals: \(\int\sqrt{x^2-4x+2dx}\)

∫ √(x2-4x+2)dx

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To Find : \(\int\sqrt{x^2-4x+2dx}\)

Now, \(\int\sqrt{x^2-4x+2}dx\) can be written as \(\int\sqrt{x^2-4x+2^2-2^2+2}dx\)

Here , let x\(-2=y\Rightarrow dx=dy\)

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