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+2 votes
4.9k views
in Mathematics by (15.9k points)

The value of the definite integral

\(\int\limits_{\frac{\pi}{24}}^{\frac{5\pi}{24}}\)\(\frac{dx}{1+\sqrt[3]{tan2x}}\) is :

(1) \(\frac{\pi}{3}\)

(2) \(\frac{\pi}{6}\)

(3) \(\frac{\pi}{12}\)

(4) \(\frac{\pi}{18}\)

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1 Answer

+1 vote
by (15.3k points)

\(\Rightarrow\) 2I = \(\frac{4 \pi}{24}\) \(\Rightarrow\) I = \(\frac{\pi}{2}\)

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