∫dx(1 - e^{2x}) = ?

Question

\(\int\frac{dx}{(1-e^{2x})}\) = ?

∫dx(1 - e^2x)

A.log | e^x + \(\sqrt{e^{2x}-1}\)| + c

B.log | e^-x + \(\sqrt{e^{2x}-1}\)| + c

C.- log | e^-x + \(\sqrt{e^{2x}-1}\)| + c

D. none of these

Answer 1

- 2e^2x\(\frac{dx}{dt}\) = 1

⇒ dx = - \(\frac{1}2\)\(\frac{dt}{1-t}\)