∫dx/√3x^2 + 6x + 12} = ?

Question

\(\int\frac{dx}{\sqrt{3x^2+6x+12}}\) = ?

∫dx/√3x² + 6x + 12}

A. log |(x + 1) + \(\sqrt{x^2+2x+4} \)| + c

B. \(\frac{1}3\)log |(x + 1) + \(\sqrt{x^2+2x+4} \)| + c

C.\(\frac{1}{\sqrt3}\)log |(x + 1) + \(\sqrt{x^2+2x+4} \)| + c

D. none of these

Answer 1

\(\int\frac{dx}{\sqrt{3x^2+6x+12}}\) = \(\int\frac{1}{\sqrt3}{\frac{dx}{\sqrt{x^2+2x+4}}}\)