∫dx/√{2x^2 + 4x + 6} = ?

Question

\(\int\frac{dx}{\sqrt{2x^2+4x+6}}\) = ?

∫dx/√{2x² + 4x + 6}

A. \(\frac{1}2\) log|(x +1) + \(\sqrt{x^2+2x+3}\)| + c

B.\(\frac{1}{\sqrt2}\) log|(x +1) + \(\sqrt{x^2+2x+3}\)| + c

C.\(\frac{1}2\) log| x + \(\sqrt{x^2+2x+3}\)| + c

D. none of these

Answer 1

\(\int\frac{dx}{\sqrt{2x^2+4x+6}}\) = \(\int{\frac{1}{\sqrt2}}\frac{dx}{\sqrt{x^2+4x+3}}\)