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Find the slope of the tangent to the curve

i. y = (x3 - x) at x = 2

ii. y = (2x2+3 sin x) at x = 0

iii. y = (sin 2x+cot x+2)2 at x = π/2

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\(\frac{dy}{dx}\) at (x = π/2) = 2(0+0+2)(-2-1) = -12

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