Given : A. \( \begin{bmatrix} 2& 3 \\[0.3em] 4& 5 \\[0.3em] \end{bmatrix}\) = \( \begin{bmatrix} 0& -4 \\[0.3em] 10& 3 \\[0.3em] \end{bmatrix}.\)
To find : matrix A
Formula used :
Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
IF AX = B, then A = BX -1
To find \( \begin{bmatrix} 2 & 3 \\[0.3em] 4 & 5 \\[0.3em] \end{bmatrix}^{-1}\)
Determinant of given matrix = \( \begin{bmatrix} 2 & 3 \\[0.3em] 4 & 5 \\[0.3em] \end{bmatrix}\) = 5(2) – (4)(3) = 10 – 12 = -2
Adjoint of matrix \( \begin{bmatrix} 2 & 3 \\[0.3em] 4 & 5 \\[0.3em] \end{bmatrix}\) = \( \begin{bmatrix} 5&-3 \\[0.3em] -4&2 \\[0.3em] \end{bmatrix}\)
A = \( \begin{bmatrix} -8 & 4 \\[0.3em] -19&12 \\[0.3em] \end{bmatrix}\)
A = \( \begin{bmatrix} -8 & 4 \\[0.3em] -19&12 \\[0.3em] \end{bmatrix}\)