Given : [1 x 1] \( \begin{bmatrix} 1&2&3 \\[0.3em] 4 & 5 &6\\[0.3em] 3 &2& 5 \end{bmatrix}\)\( \begin{bmatrix} 1 \\[0.3em] -2 \\[0.3em] 3 \end{bmatrix}\) = 0,
To find : x
Formula used :
Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
If A is a matrix of order a x b and B is a matrix of order c x d , then matrix AB exists and is of order a x d ,
if and only if b = c
12x + 20 = 0
12x = -20
\(\text{x}=\frac{-20}{12}=\frac{-5}{3}\)
\(\text{x}=\frac{-5}{3}\)