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If A = \( \begin{bmatrix} 1 & 0 \\[0.3em] -1 & 7 \\[0.3em] \end{bmatrix}\) and B = \( \begin{bmatrix} 0& 4 \\[0.3em] -1 & 7 \\[0.3em] \end{bmatrix},\) find (3A2 – 2B + I).

A = [(1,0)(-1,7)]

B = [(0,4)(-1,7)]

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Given : A = \( \begin{bmatrix} 1& 0 \\[0.3em] -1 & 7 \\[0.3em] \end{bmatrix}\) and B = \( \begin{bmatrix} 0& 4 \\[0.3em] -1 & 7 \\[0.3em] \end{bmatrix},\)

Matrices A and B are of order 2 x 2.

To find : (3A2 – 2B + I).

Formula used :

Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj

A2 is a matrix of order 2 x 2.

3A2 – 2B + I

3A2 – 2B + I = \( \begin{bmatrix} 4&-8 \\[0.3em] -22 &134 \\[0.3em] \end{bmatrix}\)

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