n(S) = Total number of elementary events= 12.
(i) Favourable number of elementary events that points to 10 = 1
`therefore " Required probability "(1)/(12)`
(ii) Let A be the event "point of the arrow head towards an odd number"
`therefore" "n(A)={1,3,5,7,9,11}=6`
`therefore" "P(A)=(n(A))/(n(S))=(6)/(12)=(1)/(2)`
(iii) Let E be the event "pointing towards a number which is a multiple of 3"
`therefore" "n(E)={3,6,9,12}=4`
`therefore" "P(E)=(n(A))/(n(S))=(4)/(12)=(1)/(3)`