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A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls. A ball is drawn at random from the bag. Find the probability that it is (i) black, (ii) not green ,(iii) red or white, (iv) neither red nor green.

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Correct Answer - ` (i) 2/15 (ii) 11/15 (iii) 3/5 (iv) 2/5`
Total number of balls = 4+5+2+4 = 15.
(i) Number of black balls = 2.
P(getting a black ball) = `2/15`.
(ii) Number of balls which are not green = ` 4+5+2= 11`.
P(getting a ball which is not green) ` 11/15`.
(iii) Number of balls which are red or white = 5 +4 = 9 .
P(getting a ball which is red or white ) = ` 9/15 = 3/5`.
(iv) Number of balls which are neither red nor green = 4+2 = 6.
P(getting a ball which is neither red nor green ) = ` 6/15 = 2/5`.

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