Given A = \( \begin{bmatrix} 3& 2& -1 \\[0.3em] -5& 0 & -6 \\[0.3em] \end{bmatrix}\) and B = \( \begin{bmatrix} -4& -5& -2 \\[0.3em] 3&1 & 8 \\[0.3em] \end{bmatrix}\)
To Prove: (A + B)’ = A’ + B’
Proof: Let us consider C = A + B
Now LHS = C’
To find RHS, we will find transpose of matrix A and B
LHS = RHS
Hence proved.