Given,
`r1=8cm, r2=20cm, h=16cm`
Volume of container=`1/3pi(r1^2 + r2^2 +(r1)(r2))h`
=`22/7*(1/3)*(8^2+20^2 +20*8)*16 cm^3`
=`(22*208*16/7) cm^3`
=`(22*208*16/(7*1000))litres`
Cost of milk=`(22*208216/7)*20= Rs 28.16`
Total Surface area= `pi(r1+r2)l + pi(r1)^2`
= `22/7*624 cm^2`
Total Required cost=`22/7*624*8/100=Rs 156.89`