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2 cubes each of volume `64 c m^3`are joined end to end. Find the surface area of the resulting cuboid.

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Let side of the cubes in cm is `a`.Then, `a^3 = 64=> a = 4`
If we join these two cubes end to end, then surface area of resulting cuboid will have `10` faces
as two internal faces are common will not be included in the cuboid.
Please refer to video for graphical explanation.
So, surface area of resulting cuboid, `A = 10**`Surface area of each face
`A = 10**(4)^2 = 160cm^2`

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