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In one fortnight of a given month, there was a rainfall of 10 cm in a river valley. If the area of the valley is `97280 k m^2`, show that the total rainfall was approximately equivalent to the addition to the normal water of three rivers each 10

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Total Volume=A*10 m
=`97280*10^6*0.1 m`
=`9728*10^6 m^3`
per day=`695*10^6m^3`
3(Volume of single river)=`3*(1072*75*3)`
=`7236*10^6 m^3`.

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