Given A = \(
\begin{bmatrix}
3 &-4 \\[0.3em]
1 & -1 \\[0.3em]
\end{bmatrix}\)
To prove: A - A’ is a skew-symmetric matrix.(Note: A matrix P is skew-symmetric if P’ = -P)
Proof: First we will find the transpose of matrix A
A' = \(
\begin{bmatrix}
3 &-1 \\[0.3em]
-4 & -1 \\[0.3em]
\end{bmatrix}\)
Let us take P = A - A
\(\Rightarrow \) P' = P
Hence A - A’ is a skew symmetric matrix.