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If y = \(\sqrt{sin\,x+\sqrt{sin\,x+\sqrt{sin\,x......\infty}}}\) then dy/dx = ?

√(sin x+√(sin x+√(sin x....∞)))

A. sin x/(2y - 1)

B. cos x/(y - 1)

C. cos x/(2y - 1)

D. none of these

1 Answer

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Best answer

Answer is: C. cos x/(2y - 1)

Given:

⇒ y = \(\sqrt{sin\,x+\sqrt{sin\,x+\sqrt{sin\,x+....\infty}}}\)

We can write it as

⇒ y = \(\sqrt{sin\,x+y}\)

Squaring we get

⇒ y= sin x + y

Differentiating

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