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in Derivatives by (50.9k points)
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The value of k for which f(x) = \(\begin{cases} \frac{3x+4\,tan\,x}{2}, & when\,x\neq0 \\ k, & when\,x=0 \end{cases}\) is continuous at x = 0, is

3x+4 tan x/2, when x ≠ 0

k, when x = 0

A. 7

B. 4

C. 3

D. none of these

1 Answer

+1 vote
by (49.4k points)
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Best answer

Answer is: A. 7

⇒ f(x) = 3x+4 tan x/x is continuous at x = 0.

⇒ f(x) = 3+4

∴ K = 7

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