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A chord of a circle of radius 15 cm subtends an angle of `60o`at the centre. Find the areas of the corresponding minor and major segments of the circle.

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area(minor segment)=area(sector OAB)-area(triangleOAB)
=`theta/360^0pir^2-sqrt3/4r^2`
=`60/360*pi 15^2-sqrt3/4 15^2`
=20.4375 `cm^2`
area(major segment)=`pir^2-20.4375`
=`3.14*225-20.4375`
=686.0625 `cm^2`

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